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Start your free trialdebasis nath
11,650 Pointsmessy_list pop
why is it showing error ?
messy_list = ["a", 2, 3, 1, False, [1, 2, 3]]
# Your code goes below here
messy_list.pop(0)
messy_list.insert(0,1)
1 Answer
debasis nath
11,650 PointsHey there! thanks for your reply but I have got a solution on my own
messy_list.insert(0,messy_list.pop(3)) which is very simple and worked for me.
James Reinhold
12,361 PointsJames Reinhold
12,361 PointsIt is showing an error because 1 is at index 3 and not index 0.