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Yukiru Kannazuki
3,036 Pointsmost_classes() takes 0 positional arguments but 1 was given.
Here, I'm attempting to return the teacher (Friend) from teacher_dict with the most classes (Languages). However, it says I have a positional argument, and I'm not quite sure what it means by that. I wasn't quite sure either how the **dict_name method worked, so if you could explain that a bit to me, It'd be appreciated. Thanks.
# The dictionary will be something like:
# {'Jason Seifer': ['Ruby Foundations', 'Ruby on Rails Forms', 'Technology Foundations'],
# 'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Often, it's a good idea to hold onto a max_count variable.
# Update it when you find a teacher with more classes than
# the current count. Better hold onto the teacher name somewhere
# too!
#
# Your code goes below here
teacher_dict = {'Yuki': ['Japanese', 'German', 'English'], 'Avi': ['English'], 'Jean': ['Philipino', 'English']}
def most_classes():
max_count = 0
best_teach = []
for person in teacher_dict:
subjects = len(person[key])
if subjects > max_count:
best_teach = person
max_count = subjects
the_teacher = {'classes': max_count, 'name': best_teach}
return ("Mr. {} has the most classes. ({})").format(**the_teacher)
2 Answers
Kenneth Love
Treehouse Guest TeacherYour function doesn't accept any arguments but it should. You need to do the work (figuring out the teacher with the most classes) on the dictionary that comes in, not on one you've defined in the file.
Yukiru Kannazuki
3,036 PointsThanks, I can never figure out whether I need to do one on my own or let one come in.
Kenneth Love
Treehouse Guest TeacherYou'll pretty much always let one come in.