most_courses

Question

Not sure how to count the number of courses and return a key value. The .values() and .key() methods turn the dict into a list, which I think is the wrong way to go about the problem. But I don't know how to work with the dict as is.

teachers.py

# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
#  'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.


def num_teachers(single_arg):
    return len(single_arg)

def num_courses(single_arg):
    my_list = []
    my_value = single_arg.values()
    for value in my_value:
        my_list.extend(value)
    return len(my_list)

def most_courses(single_arg):
    maxItem = 0
    for value in single_arg:
        num_value = len(value)
    if num_value > maxItem:
           maxItem = value
    return maxItem

Answer 1 · 2017-11-15T22:35:35Z

November 15, 2017 10:35pm

If you're iterating through the keys, you can always use the key as an index into the dictionary to access the associated values. And this would certainly be one way to approach this challenge.

But you can also get them both at the same time using "items":

    for key, value in some_dict.items():

Welcome to the Treehouse Community

Looking to learn something new?

Andrew McLane

Andrew McLane

most_courses

1 Answer

Steven Parker

Steven Parker