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Adrianne Browning
2,602 PointsMove the 1 to position 0. You can do this in one step with .pop() and .insert().
helppppppppppppppppppppppppppp
the_list = ["a", 2, 3, 1, False, [1, 2, 3]]
# Your code goes below here
2 Answers
Gordon Reeder
2,521 PointsNo need for the temp variable. It can be done with pop() and .insert() on a single line.
the_list.insert(0, the_list.pop(3))
Chris Freeman
Treehouse Moderator 68,441 PointsFrom the Lists Redux manipulating lists Challenge:
Move the 1 to position 0. You can do this in one step with .pop() and .insert().
Given the list:
the_list = ["a", 2, 3, 1, False, [1, 2, 3]]
The "1" is the 4-th item in the list and can be reference as list[3] (using 0-based counting).
Use the pop() method to "pop" an item off of the list. Assign this to a temp variable:
temp = the_list.pop(3)
Use the insert() method to "insert" an item into a list at a specific position. Inserting temp into the_list at position 0::
the_list.insert(0, temp)
All together, running in ipython, it would look like:
In [84]: the_list = ["a", 2, 3, 1, False, [1, 2, 3]]
In [85]: the_list[3]
Out[85]: 1
In [86]: temp = the_list.pop(3)
In [87]: temp
Out[87]: 1
In [88]: the_list
Out[88]: ['a', 2, 3, False, [1, 2, 3]]
In [89]: the_list.insert(0, temp)
In [90]: the_list
Out[90]: [1, 'a', 2, 3, False, [1, 2, 3]]