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Kang-Kyu Lee
52,045 Pointsmy answer doesn't pass..
import random
def nchoices(an_iterable, choose_num):
list_of_items = []
for _ in range(choose_num):
pop_item = an_iterable.pop(random.randrange(len(an_iterable)))
list_of_items.append(pop_item)
return list_of_items
iterable = [1,2,3,4,5,6,7,8,9]
integer = 4
nchoices(iterable,integer)
Maybe I did it wrong, only I couldn't figure what it is... it works at workspace
2 Answers
Kenneth Love
Treehouse Guest TeacherIt's not that there's anything that says to allow duplicates, nothing says to not allow duplicates, so you shouldn't assume that.
Jason Anello
Courses Plus Student 94,610 PointsHi kang kyu lee,
I don't think the challenge is specific enough on this but I think it wants the solution to allow duplicates. Whereas, you're popping off items and shortening the iist and making sure the same one isn't picked twice.
I changed your code so that instead of popping off the item at that random index you access the item at that index and it passed the challenge.
I have not been through this course so I don't know if there is something in the videos that would have hinted that you should allow duplicates here.
Kang-Kyu Lee
52,045 PointsKang-Kyu Lee
52,045 PointsThank you folks. It's given the function
nchoices()takes the number of items to return, I assumed the duplicates might not be counted, and I tried the same one already picked not be an option. However, because not given as it said, then both possible answers should be working?Kenneth Love
Treehouse Guest TeacherKenneth Love
Treehouse Guest TeacherTo me, eliminating duplicates would require the explicit instruction to do so. I'll add a note to the instructions, though, to prevent future confusion.