My answer when executed gives output properly but it is giving error here

Question

EXAMPLES

squared(5) would return 25

def squared(num1): try: num1=int(num1 ** 2)

except TypeError:
    return(len(num1) * num1)

squared("2") would return 4

squared("tim") would return "timtimtim"

squared.py

# EXAMPLES
# squared(5) would return 25
def squared(num1):
    try:
        num1=int(num1 ** 2)

    except TypeError:
        return(len(num1) * num1)
# squared("2") would return 4
# squared("tim") would return "timtimtim"

Answer 1 · 2017-02-15T16:57:23Z

February 15, 2017 4:57pm

There are a few issues with your solution. Note that int(num1 ** 2) is different than int(num1) ** 2. The former squares num1 then converts to integer. The latter converts num1 to integer then squares it. These give different results if num1 is a float such as 3.5. It's important to read the instructions carefully in these challenges to make sure you're doing exactly what it asks you.

Another issue is that in the case where you are able to square the number, you are not returning anything.

Finally, if you are unable to convert the input to an integer, it will actually result in a ValueError rather than a TypeError, although I believe the challenge will also accept a generic 'except:' to catch all exceptions.

A full solution might look like this:

def squared(num1):
    try:
        square = int(num1) ** 2
        return square
    except ValueError:
        return len(num1) * num1

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