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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Asif Choudhury
Asif Choudhury
2,086 Points
Posted by Asif Choudhury
Asif Choudhury
2,086 Points

My code is giving right result on word_count(), still not passing the test, weird!

I have run my code in my pycharm IDE, it produces result just as it should be. I am still not passing the test! What wrong?

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(a):

    b=a.lower()
    sliced=b.split(" ")

    #a list of keys for the future dictionary    
    keys=[]
    #eliminate duplicate keys
    keys=list(set(sliced))
    #a list of values of the future dictionary
    values=[]
    for j in range(len(keys)):
        values.append(sliced.count(keys[j]))

    #building the dictionary from 2 lists:keys and vlaues
    dixionary=dict(zip(keys,values))

    return dixionary

word_count("I do not like it Sam I am")

2 Answers

Asif Choudhury
Asif Choudhury
2,086 Points
Asif Choudhury
Asif Choudhury
2,086 Points

Thanks James. Now it works.