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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by Vehid Metovic
Vehid Metovic
10,117 Points

My code work just fine in my IDLE but does Treehouse does not accept it

Works just fine

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(string) :
    string = string.lower()
    x = string.split(" ")
    dic = {}
    for i in range(len(x)):
        if x[i] in dic : 
            dic[x[i]]+=1
        else :
            dic2 = { x[i] : 1 }
            dic.update(dic2)
    return dic

1 Answer

Steven Parker
Steven Parker
231,236 Points
Steven Parker
Steven Parker
231,236 Points

You probably were not testing it quite as rigorously as the validator does. But did you notice this hint in the "Bummer" message: "Be sure you're lowercasing the string and splitting on all whitespace!" ?

To split on "all whitespace" the argument to "split" should be left blank. Giving a space as the argument causes it to split only on individual spaces.

Otherwise, it looks good!