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Start your free trialAngel Manuel Couso Jimenez
Courses Plus Student 4,402 PointsMy Solution, Is Correct?? Feedback is welcome
var html = '';
function randomRBGColor () {
var red = Math.floor(Math.random() * 256 );
var green = Math.floor(Math.random() * 256 );
var blue = Math.floor(Math.random() * 256 );
var rgbColor = 'rgb(' + red + ',' + green + ',' + blue + ')';
return '<div style="background-color:' + rgbColor + '"></div>';
}
for (var i = 0; i <= 9; i ++) {
html += randomRBGColor();
}
document.write(html);
1 Answer
Rasbin Rijal
Courses Plus Student 4,940 PointsHi Angel Manuel Couso Jimenez ,
Your code is correct and works very well. If you would like to improve further, you can follow the DRY (Don't Repeat Yourself) approach.
In your code, inside randomRGBColor function you have 3 variables : red, green and blue. You have repeated the code in those variable. You may keep the repeated code ( which is creating a random RGB value ) inside a separate function. Then, you can call that function from those variables.
Happy Learning! Rasbin
Mathew Yangang
4,433 PointsMathew Yangang
4,433 PointsIt works ! thanks a lot. If only you can add more explanations so that i can understand it more better. But it works