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aishwary bhutani
Courses Plus Student 100 Pointsneed a quick help
how to solve this?
# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
# 'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.
def num_teachers(string):
return len(string)
def num_courses(strin):
return len(strin.items())
3 Answers
Robert Daly
2,287 Pointsdef num_teachers(str1): return len(str1)
def num_courses(str1):
count = 0
for teach in str1:
count = count + len(str1[teach])
return count
Mduduzi Frederick Dube
8,886 PointsHie Aishwari
Your argument is a dictionary, your first function is just returning the length of that dictionary instead. Try using the .keys() method to get a list of the dictionary's keys which list will be a list of teachers. return the length of that list as shown below.
def num_teachers(dicto):
return len(dicto.keys())
Mduduzi Frederick Dube
8,886 PointsFor your second task you need to iterate over the dictionary's values, ie for a dictionary, dicto we do dicto.values(). Remember to have a variable that will increament as you iterate over that value, try:
def num_courses(dicto):
count = 0
for val in dicto.values(): # iterate over the dictionaries values one at a time
count += len(val) # increament the variable count by the length of the value
return count