Need help with Key and Value, also to compare them to find the most classes.

Every step of indentation has to be the same. Python doesn't really care how much it is, just so long as it's consistent. The style guide recommends 4, though.

def most_classes(x):
    max_count = {}
    busy_teacher = 0

    for keys, values in x:
        if len(value) >= max_count:
            len(value) = max_count

Notice how each block's contents are indented 4 spaces more?

Just to clarify, I'm not saying the above code is correct. Just showing you how to properly format it.

Good luck!

A lot of your code is good. Look at the len(value) = line (you'd want to assign len(value) to something, not something to len(value). And you probably don't want max_count to a dictionary or busy_teacher to be an integer.

Which part are you stuck on? The above comment should fix the one actual problem with your code (the assignment part). How do you assign a variable?

Why is your max_count a dictionary? It's going to be holding a number, right? So shouldn't it be an int?

Why is busy_teacher an integer? It's going to hold a string (the teacher's name), so shouldn't it start as an empty string?

Yes, you'll need both a for loop and an if.

Let's break it down step-by-step.

1. Start a function named most_classes. It'll take an argument that will be a dictionary of teachers.
2. Set up a variable for holding the current highest number of classes. Right now this should be 0 because you've seen no classes.
3. Set up a variable for holding the teacher with the highest number of classes. Right now this should be an empty string because you've seen no teachers.
4. Loop though all of the teachers in the dictionary.
5. Find out the length of the current teacher's list of classes.
6. If they have more classes than the current high count, set the high count to the length of the current teacher's classes and set the busiest teacher to be the current teacher.
7. When we're done with the loop, send back the busiest teacher variable.

Think you can spot your problems and solutions from here?

If your dictionary of teachers is called teachers, and your for loop is for teacher in teachers:, then you'd want current_highest_classes = len(teachers[teacher]) since the value of that teacher's key in the dict is what we want to get the length of.

OK, slow down, take it a step at a time.. You're putting the count into both high count variable and the busy teacher variable. And you're returning a busy_teacher variable that I don't see you actually creating anywhere.

def most_classes(teachers):
    busy_teacher = ''
    high_count = 0

    for teacher in teachers:
        if len(teachers[teacher]) > high_count:
            high_count = len(teachers[teacher])
            busy_teacher = teacher

    return busy_teacher

Again, your code isn't indented as it should be. Also, as with lists, strings, etc, you can get the length/size of a dictionary with the len() attribute. I'm sure you can find a way to do your function much more easily with that information.

You still aren't indenting your code correctly. Python's layout is 100% defined by whitespace, so you have to format your code correctly.

After that, can you walk me through your thought process for your code? What are you expecting each line to do?

I'm not disappointed in you, Ronnie! I want you to succeed! Just trying to find out what I haven't explained well enough.

Walk me through your logic. What are you expecting each line to do?

No, no. I know what you did, I want to know why you did them.

Like, why do a for loop there? Why do an if statement inside of it? What are you checking and for what reason?

That's a good formula for counting if you need a condition. Like, only count the items in this list where they have a red shirt. When you don't have that condition, though, len() works better.

This step of the challenge doesn't need if or for statements since there's no condition to work through. You just need to get the number of keys in the dictionary.