Need some guidance on passing this challenge

Question

zippy.py

# combo([1, 2, 3], 'abc')
# Output:
# [(1, 'a'), (2, 'b'), (3, 'c')]
# If you use .append(), you'll want to pass it a tuple of new values.
def combo():
    h=[]
    g=[]
    h=tuple(combo[0])
    g=tuple(combo[1])
    for step in combo:
        return ('{}:{}'.format(g[0],h[0]))+('{}:{}'.format(g[1],h[1]))

Answer 1 · 2016-06-16T20:01:09Z

June 16, 2016 8:01pm

The enumerate function is a built-in function in Python and adds a counter to an iterable.

Here is some information on enumerate in the python docs. https://docs.python.org/3/library/functions.html?highlight=enumerate#enumerate

Using the zip function is by far the easiest although you haven't been introduced to it yet in the course here's some documentation. https://docs.python.org/3/library/functions.html?highlight=enumerate#zip

def combo(item1, item2):
    new_list = []
    for index, item in enumerate(item2):           
        new_list.append((item1[index], item))
    return new_list

Answer 2 · 2016-06-16T19:06:22Z

June 16, 2016 7:06pm

def combo(one, two): return list(zip(one,two))

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Laknath Gunathilake

Laknath Gunathilake

Need some guidance on passing this challenge

2 Answers

Russell Sawyer

Russell Sawyer

Freddy Venegas

Freddy Venegas

Cindy Lea

Cindy Lea