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Royce Sithole
2,625 Pointsno clue.
hello guys. i need a bit of assistance. i have no idea what they are asking me to do here may someone please explain the question to me.
Let's test unpacking dictionaries in keyword arguments. You've used the string .format() method before to fill in blank placeholders. If you give the placeholder a name, though, like in template below, you fill it in through keyword arguments to .format(), like this: template.format(name="Kenneth", food="tacos") Write a function named string_factory that accepts a list of dictionaries as an argument. Return a new list of strings made by using ** for each dictionary in the list and the template string provided.
# Example:
# values = [{"name": "Michelangelo", "food": "PIZZA"}, {"name": "Garfield", "food": "lasagna"}]
# string_factory(values)
# ["Hi, I'm Michelangelo and I love to eat PIZZA!", "Hi, I'm Garfield and I love to eat lasagna!"]
1 Answer
james south
Front End Web Development Techdegree Graduate 33,271 Pointsyou are given a list of dicts and a template. you want to return a list of strings made from the template and the contents of the dicts in the list. you need to loop through the list of dicts and for each dict in the list, append to a new list the template formatted (format method) with the values in each dict using the keyword args (two asterisks). then return that new list.