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Vic A
5,452 PointsNot quite sure how to tackle this.
this is as far as i got :/
# Example:
# values = [{"name": "Michelangelo", "food": "PIZZA"}, {"name": "Garfield", "food": "lasagna"}]
# string_factory(values)
# ["Hi, I'm Michelangelo and I love to eat PIZZA!", "Hi, I'm Garfield and I love to eat lasagna!"]
template = "Hi, I'm {name} and I love to eat {food}!"
def string_factory(**kwargs):
output = []
for i in **kwargs:
output.append(template.format(**kwargs))
2 Answers
james south
Front End Web Development Techdegree Graduate 33,271 Pointsyou are on the right track. you don't need the word kwargs anywhere. the parameter to the function can be whatever you want, the argument to be passed to the function is the list of dicts. as you loop through the list of dicts, your loop variable will hold each dict and in the loop you basically have that part already, you are appending the template formatted with the two asterisks and the loop variable, so **i to use your loop variable. and then return the answer.
Vic A
5,452 Pointsawesome. Thanks for the explanation. I understand know