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Start your free trialVictor Gavojdea
11,796 PointsNot sure what to put as the search pattern, nothing I'm trying seems to be working.
I'm sure its obvious but I'm stumped. Looking at solutions on stackoverflow involving [a-zA-Z] is just confusing me more.
1 Answer
Chris Freeman
Treehouse Moderator 68,457 PointsThe challenge asks "return a list of the words in the string that are 'count' word
characters long or longer". In a regular expression search a word character is represented with \w
. To find count
many characters, you can multiply this short string by count
. Then to also find words of greater length, you can search for \w*
which means "zero or more word characters". putting these together you get:
import re
βdef find_words(count, string):
return re.findall(r'\w' * count + '\w*', string)
Victor Gavojdea
11,796 PointsVictor Gavojdea
11,796 PointsThank you. :)
Ivan Bodnar
2,419 PointsIvan Bodnar
2,419 PointsThanks Chris, I was stuck too, I was trying to do it with .format()