Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

JavaScript JavaScript Basics (Retired) Making Decisions with Conditional Statements Using Comparison Operators

Shawn Wilson
seal-mask
.a{fill-rule:evenodd;}techdegree
Shawn Wilson
iOS Development Techdegree Student 7,049 Points

Not sure where I'm going wrong here.. help please.

So see the challenge question and my solution below.

Q: Add a conditional statement that tests if the value in the variable a is greater than the value in variable b. If it is, pop up an alert with the message 'a is greater than b'; also add an else clause that pops up the message 'a is not greater than b'.

my solution:

var a = 10; var b = 20; var c = 30;

if (parseInt( a ) > parseInt( b ) ) { alert('a is greater than b'); } else { alert('a is not greater than b'); }

the error i receive from treehouse checker tool is:

" Bummer! Did you use the > symbol to test if a is greater than b? "

script.js
var a = 10;
var b = 20;
var c = 30;
index.html
<!DOCTYPE HTML>
<html>
<head>
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
  <title>JavaScript Basics</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>
Gary Ford
Gary Ford
14,475 Points

Try:

if( a > b ) { 
    alert( a + ' is greater than ' + b); 
}else { 
    alert(a + ' is not greater than ' + b);
}

no need to use parseInt() (the variable values are already integers). Also use concatenation for your string that is shown in your alert box.

1 Answer

Carlos Estrada
Carlos Estrada
6,959 Points

Try using just the variables w/o the 'parseInt(...)' function inside the 'if' statement. That function takes a string as a parameter and returns an int. In your case the variables are already integers and there is no need to convert them.