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PHP Build a Simple PHP Application Creating the Menu and Footer Variables and Conditionals

Brian Platt
Brian Platt
5,009 Points
Posted by Brian Platt
Brian Platt
5,009 Points

Not sure why my code isn't passing

Hey guys, why isn't this code passing? I'm sure I'm doing something obviously wrong Thanks! Brian

<?php $flavor= "vanilla"; if ($flavor == "vanilla"; echo "<p>Your favorite flavor of ice cream is "; echo "vanilla"; echo ".</p>"; echo "<p>Randy's favorite flavor is cookie dough, also!</p>";

?>

3 Answers

Mario Mitchell
Mario Mitchell
18,789 Points

Hi,

You forgot the closing ) bracket for the condition. Also you need { } curly brackets to hold the statements it will do if the condition is true. Also should be no semicolon after vanilla.

<?php $flavor= "vanilla"; if ($flavor == "vanilla") { echo "Your favorite flavor of ice cream is "; echo "vanilla"; echo "."; echo "Randy's favorite flavor is cookie dough, also!"; }

Brian Platt
Brian Platt
5,009 Points
Brian Platt
Brian Platt
5,009 Points

Thanks I knew that it was something obvious! Thanks again!

Mario Mitchell
Mario Mitchell
18,789 Points
Mario Mitchell
Mario Mitchell
18,789 Points

No problem, glad to help.