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Start your free trialAlan Snyder
1,088 PointsNSArray *drinks = @[@"juice", @"water", @"coffee"]; for(NSString *string in drinks){ NSLog("
Objective C basics skill test
NSArray *drinks = @[@"juice", @"water", @"coffee"];
for(NSString *string in drinks){
NSLog("%@", string);
}
1 Answer
William Li
Courses Plus Student 26,868 PointsHi, Alan, your code is missing a @ sign before the NSLog output.
NSLog(@"%@", string);
Hope it helps.