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iOS Objective-C Basics (Retired) Foundation Framework NSArray

Alan Snyder
Alan Snyder
1,088 Points

NSArray *drinks = @[@"juice", @"water", @"coffee"]; for(NSString *string in drinks){ NSLog("

Objective C basics skill test

nsarray.mm
NSArray *drinks = @[@"juice", @"water", @"coffee"];
for(NSString *string in drinks){
NSLog("%@", string);
}

1 Answer

William Li
PLUS
William Li
Courses Plus Student 26,868 Points

Hi, Alan, your code is missing a @ sign before the NSLog output.

 NSLog(@"%@", string);

Hope it helps.