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Start your free trialDaniel Harrison
2,944 PointsObjects Challenge
I cannot get the syntax correct for Task 4 of 4
Challenge Task 4 of 4
PalprimeChecker objects have a method called isPalprime(). This method does not receive any arguments. It returns true if the number property contains a palprime, and it returns false if the number property does not contain a palprime. (Tip: 17 is not a palprime.) Turn the second echo statement into a conditional that displays "is" or "is not" appropriately. The conditional should call the isPalprime method of the $checker object. If the isPalprime method returns true, then echo "is"; otherwise, echo "is not".
Guidance would be appreciated
Thanks
2 Answers
Serhii Lihus
6,352 PointsHi Daniel!
In code below you can find answer.
But, despite that, what problems with syntax do you have? Can you show us your code sample? After that we can direct you to the right point and give more specific answers :)
<?php
include("class.palprimechecker.php");
$checker = new PalprimeChecker();
$checker->number = 17;
echo "The number ".$checker->number;
echo ($checker->isPalprime())? "is" : "is not";
echo " a palprime.";
?>
Best regards.
Serhii Lihus
6,352 PointsПривет )
Пишешь
```html
<p>между ними вставляешь код</p>
```
<p>между ними вставляешь код</p>
вместо html можно писать php, сss, js. Вот тут статейка с дополнительными пояснениями
https://teamtreehouse.com/community/posting-code-to-the-forum
Andrew Dovganyuk
10,633 PointsСпасибо Серега за инфу!!!
Andrew Dovganyuk
10,633 PointsAndrew Dovganyuk
10,633 PointsСерега привет подскажи пожалуйста как ты скрин с кодом отображаешь?