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JavaScript AJAX Basics (retiring) Programming AJAX Create a callback

On line 2 of the app.js file, add an onreadystatechange event handler. Add an anonymous function, but don't put any code

On line 2 of the app.js file, add an onreadystatechange event handler. Add an anonymous function, but don't put any code inside it.

app.js
var xhr = new XMLHttpRequest();
xhr.onreadystatechane = function () {
xhr.open('GET', 'sidebar.html');
xhr.send();
index.html
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>AJAX with JavaScript</title>
  <script src="app.js"></script>
</head>
<body>
  <div id="main">
    <h1>AJAX!</h1>
  </div>
  <div id="sidebar"></div>
</body>
</html>

5 Answers

Ben Spears
Ben Spears
19,148 Points
var xhr = new XMLHttpRequest();

xhr.onreadystatechange = function() {
xhr.open('GET', 'sidebar.html');
xhr.send();
};
Ben Spears
Ben Spears
19,148 Points

xhr.onreadystatechane = function () {

you left the 'g' out of change

Ben Spears
Ben Spears
19,148 Points

Are you closing the {} in the function? I dont see the closing brace after the inner code.

var xhr = new XMLHttpRequest(); xhr.onreadychange = function (){ xhr.open('GET', 'sidebar.html'); xhr.send();

i have written as you suggested above. but am still getting the bummer that says syntax error.

You need to have 'state' added to make xhr.onreadystatechange =...

var xhr = new XMLHttpRequest();

xhr.onreadystatechange = function() { xhr.open('GET', 'sidebar.html'); xhr.send(); };