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Start your free trialtomtrnka
9,780 PointsPassing a dictionary into **kwargs ???!!
class Thief:
sneaky = True
def __init__(self, name, sneaky=True, **kwargs):
self.name = name
self.sneaky = sneaky
for key,value in kwargs.items():
setattr(self, key, value)
I tried to pass a dictionary as value into the **kwargs parameter but it doesnt work. No attributes age or skin were created for the instance 'brother'.
brother = Thief("Ivan", {'skin':'too soft', 'age':'too old'})
That means I can pass only variable arguments into **kwargs (meaning: age='too old', skin='too soft') ?? Or is there a way to extract this dictionary from **kwargs and assign the values into variables ?? Thanks a lot!
1 Answer
Michael Hulet
47,913 PointsYou totally can pass in a dictionary for attributes like you're trying to do, you just also have to unpack it at the call site, like this:
# Notice the extra ** before the dictionary here
sister = Thief("Emily", **{'skin': 'kinda rough tbh', 'age': 'younger than me'})
print(sister.skin)
>>> kinda rough tbh
The extra **
is what tells Python that it should use that dictionary as keyword arguments. Otherwise, it'll think it's just another parameter. For example, look at what happens when you print
out brother.sneaky
in the code you posted 😉
brother.sneaky
>>> {'skin': 'too soft', 'age': 'too old'}
tomtrnka
9,780 Pointstomtrnka
9,780 PointsThank you! makes sense :)