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3,588 Pointspassing an argument to function
After your newly created returnValue function, create a new variable named echo. Set the value of echo to be the results from calling the returnValue function. When you call the returnValue function, make sure to pass in any string you'd like for the parameter.
function returnValue (chaitu,pintu) {
var echo = chaitu + pintu;
return echo;
}
alert(returnValue("66,77"));
<!DOCTYPE HTML>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>JavaScript Basics</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>
1 Answer
Steven Parker
231,275 PointsAll the work for task 2 should be done "After your newly created returnValue
function". The function itself should remain as it was when it passed task 1.
Also, the challenge only needs you to create and set the value of "echo". You won't need to call "alert".
aleti chaitanya
3,588 Pointsaleti chaitanya
3,588 Pointsthanks steven.