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Start your free trialdavid noe
579 PointsPHP Basics: Challenge Task 2 of 3
The task is too vague. There are numerous ways of determining if the string Mike.
<?php
$name = "Mike";
if( name = 'Mike'){
$printname = "Mike"
}
else{
$prntname = "N/A"
}
?>
3 Answers
david noe
579 PointsBecause I found the instruction vague, I really try too hard with this and moved on about an hour ago.
Julian Gutierrez
19,201 PointsThere is no need for an else statement or $printname in this challenge. In the if conditional you need to use the variable $name and check for equality by using a double equal sign rather than a single equal sign which is the assignment operator.
Tom Bedford
15,645 PointsHi David
I've not looked at the challenge yet but I can see there is a typo in your code.
Inside else
you use $prntname
(missing the letter i
) instead of $printname
.
Does it work with that fixed?