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PHP Build a Simple PHP Application Creating the Menu and Footer Variables and Conditionals

Carla Thomas
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.a{fill-rule:evenodd;}techdegree
Carla Thomas
Front End Web Development Techdegree Student 16,039 Points
Posted by Carla Thomas
.a{fill-rule:evenodd;}techdegree
Carla Thomas
Front End Web Development Techdegree Student 16,039 Points

PHP Conditionals

Here are the instructions for the below challenge:

* Change the value in the flavor variable to cookie dough. *

So, I am changing this

$flavor = "strawberry";

to this

$flavor = "cookie dough";

but that is not the correct answer. I am obviously misunderstanding the instructions. What am I doing wrong? Here is the full code:

<?php
$flavor = "strawberry";

echo "<p>Your favorite flavor of ice cream is ";
echo $flavor;
echo ".</p>";
if ($flavor == "strawberry") {
  echo "<p>Randy's favorite flavor is strawberry, also!</p>";
} 
if ($flavor == "cookie dough") {
"<p>Randy's favorite flavor is cookie dough, also!</p>";
}
?>

1 Answer

Ivan Uvarov
Ivan Uvarov
22,403 Points
Ivan Uvarov
Ivan Uvarov
22,403 Points

You forgot to add echo command inside second if statement. Here's the correct code:

<?php

$flavor = "cookie dough"; 

echo "<p>Your favorite flavor of ice cream is ";
echo $flavor;
echo ".</p>";
if ($flavor == "cookie dough") {
    echo "<p>Randy's favorite flavor is cookie dough, also!</p>";
}
?>