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Python Python Collections (Retired) Dictionaries Membership

Posted by luvhappysmile365
luvhappysmile365
615 Points

Please advise!!!

I am a newbie in programming & struggling with dictionary/list problem, Please advise!!!

counts.py 
# You can check for dictionary membership using the
# "key in dict" syntax from lists.

### Example
# my_dict = {'apples': 1, 'bananas': 2, 'coconuts': 3}
# my_list = ['apples', 'coconuts', 'grapes', 'strawberries']
# members(my_dict, my_list) => 2
my_dict = {'happy': 1, 'smile': 2, 'everyday': 3}
my_list = ['happy', 'smile', 'everyday', 'forever']

def members(my_dict, my_list):
  count = 0
  for a_key in a_dict.keys (): 
    if a_key in a_list:
      count += 1 
  return count

1 Answer

Hanley Chan
Hanley Chan
27,771 Points
Hanley Chan
Hanley Chan
27,771 Points

Hi,

Your code is correct, but you are using the wrong dictionary and list. You are supposed to use the dictionary and list that were passed in as arguments. There is no need to create your own dictionary and list.

def members(my_dict, my_list):
  count = 0
  for a_key in my_dict.keys(): 
    if a_key in my_list:
      count +=1
  return count
luvhappysmile365
luvhappysmile365
615 Points

HI Hanley, thank you very much for your kind advice and quick reply to my question :)