Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialJohn Schaub
5,167 PointsPlease check my answer.
I'm not sure where I'm going wrong here.
The method below checks the speed of a car and returns a string value: either "safe" or "unsafe". Return "safe" if: The car_speed passed in as an argument is greater than or equal to the number 40. The car_speed passed in as an argument is less than or equal to the number 50. Otherwise, return "unsafe". Hint: You should use the && logical operator to accomplish this task. :)
def check_speed(car_speed)
# write your code here
if (car_speed >==40) && (car_speed <== 50)
puts "safe"
elsif (car_speed >50)
puts "unsafe"
end
2 Answers
William Li
Courses Plus Student 26,868 PointsThere're some syntactical & logical issues in your codes there.
- The use of
puts
instead ofreturn
- >== and <== are illegal symbols in Ruby
- first condition is ok asides from the comparison symbols, however, it should've been followed by the
else
clause instead of anotherelsif
. - no closing
end
keyword for the conditional statement.
So the corrected version of your code is sth like this
def check_speed(car_speed)
# write your code here
if (car_speed >= 40) && (car_speed <= 50)
return "safe"
else
return "unsafe"
end
end
Hope it helps.
Emil Nastase
4,396 PointsYou just save my night William Li ... Thanks
John Schaub
5,167 PointsJohn Schaub
5,167 PointsWilliam,
Thank you for your input. I see where I was taking this. I was reading into the question.