Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Collections (2016, retired 2019) Dictionaries Word Count

Ihar Khasianevich
Ihar Khasianevich
2,807 Points
Posted by Ihar Khasianevich
Ihar Khasianevich
2,807 Points

Please check my function. I think this is the right function. But it doesn't pass your test.

I have tested it on treehouse workspace, and get the same result that's in your comments

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(sentense):
    sentense = sentense.lower()
    words = sentense.split(" ")

    result = {}
    for w in words:
        w = w.strip()
        if w != '':
            if w in result:
                result.update({w: result[w] + 1})
            else:
                result[w] = 1
    return result

1 Answer

james south
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
james south
Front End Web Development Techdegree Graduate 33,271 Points
james south
.a{fill-rule:evenodd;}techdegree seal-36
james south
Front End Web Development Techdegree Graduate 33,271 Points

the error tells you to split on all whitespace, but you are only splitting on the space character. there are other whitespace characters like tab and newline. use a less-restrictive argument for split.