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Start your free trialyusuf patat
572 Pointsplease help
help me!
def even_odd():
number=int(input("write a even number "))
if number %2==0:
True
else:
False
1 Answer
Oszkár Fehér
Treehouse Project ReviewerHi Yusuf. Your method it's almost finished, first of all you don't need the user "input" method, the number it should be provided in the method as an argument
def even_odd(number):
From here the if statement it's ok just it's missing the return keyword
if number % 2 == 0:
return True
else:
return False
or short version
if number % 2 == 0:
return True
return False
in this case you don't need to specify the "else" to, the if already taking care to not pass False if the remainder it's 0 Also for best practice use the right spacing between elements
number % 2 == 0
not
number%2==0
This is still working but for better reading it's better with spacing and also in the future it will not cause headache. I hope it will help you to understand. Happy coding