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ALEX PAYOD
Python Web Development Techdegree Student 1,270 Pointsplease help in making the dictionary
cant turn the text into a dictionary with their counts
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(st):
a=st.lower()
b=a.split()
for c in b:
return(c, b.count(c))
2 Answers
Steve Hunter
57,712 PointsHi Alex,
I started this by creating an output dictionary that was empty. I called it output. Next, I took the incoming parameter (I called it in_string; you've called it st), made it lowercase, split it using split() and assigned that into a new variable which I called string.
Next, I created a for loop to iterate over the words in string. At each iteration I tested, using if whether the iterator (I called it word) was already contained in output. If it is there already, I incremented output[word] by 1. If it isn't already in output I set output[word] to be equal to 1.
At the end of the for loop, I returned the output dictionary.
Let me know how you get on.
Steve.
ALEX PAYOD
Python Web Development Techdegree Student 1,270 PointsThanks Steve:)))) this helped me a lot I used output.update instead of an if statement
Steve Hunter
57,712 Points