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JavaScript AJAX Basics (retiring) Programming AJAX Check for the correct ready state

Arvind Kevin Arjun Sharma
Arvind Kevin Arjun Sharma
8,272 Points
Posted by Arvind Kevin Arjun Sharma
Arvind Kevin Arjun Sharma
8,272 Points

Please help me for the answer in this challenge!

Add a conditional statement inside the onreadystatechange event handler that tests to make sure the server has sent back its complete response.

app.js 
var xhr = new XMLHttpRequest();
xhr.onreadystatechange = function() {
  if (xhr.readyState === 4) {
      if (xhr.status === 200) {
        document.getElementById('ajax').innerHTML = xhr.responseText;
      } else {
        alert(xhr.statusText);
      }
};
xhr.open('GET', 'sidebar.html');
xhr.send();
index.html 
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>AJAX with JavaScript</title>
  <script src="app.js"></script>
</head>
<body>
  <div id="main">
    <h1>AJAX!</h1>
  </div>
  <div id="sidebar"></div>
</body>
</html>

1 Answer

Raffael Dettling
Raffael Dettling
32,999 Points
Raffael Dettling
Raffael Dettling
32,999 Points

Use && instead of two if statments. You also got the wrong target in getElementById :)

var xhr = new XMLHttpRequest();
xhr.onreadystatechange = function() {
   if (xhr.readyState === 4 && xhr.status === 200) 
   {
      document.getElementById('sidebar').innerHTML = xhr.responseText;
   }

};
xhr.open('GET', 'sidebar.html');
xhr.send();