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Python Python Collections (Retired) Dictionaries Membership

Posted by Andy Christie
Andy Christie
1,361 Points

Please help me with this python code

Hi, I need to match the list items and dictionary items and return the count but I can't figure it out, please can you help me.

counts.py 
# You can check for dictionary membership using the
# "key in dict" syntax from lists.

### Example
# my_dict = {'apples': 1, 'bananas': 2, 'coconuts': 3}
# my_list = ['apples', 'coconuts', 'grapes', 'strawberries']
# members(my_dict, my_list) => 2
my_list = ["app", "ora", "cab"]
my_dict = {"app": 1, "ora": 2, "bug": 3}

def members(my_dict, my_list):
  count = ()
  for key in (my_dict, my_list):
    if my_dict[:] == my_list[:]:
      count +1
return count

1 Answer

Matthew Carr
Matthew Carr
11,220 Points
Matthew Carr
Matthew Carr
11,220 Points

1) You are setting count to (), this isn't even a number. 2) only dictionaries have keys, so it doesn't make sense to look for them in my_list (you're also make a tuple of my_dict and my_list, and then iterating over it, probably not what you are trying to do 3) this syntax copies a list my_list[:], why copy it? why not just use it directly 4) count + 1 does not update any variable, any time you are updating a variable you'll be using the assignment operator = 5) your return is at the same level of indentation as def ....; this puts it outside the function, it should be inside the function

You may want to consider going back through the videos to pick up some more of the syntax.

Andy Christie
Andy Christie
1,361 Points

Hi, thanks mate but I've done it now. I might just do as you said and start over if it gets too hard.