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Mark Weiler
579 PointsPlease help with the task sequancer!
I dont know what is the problem. Because if I copy this to workspaces it works just fine, and it returns the correct number, or string. But here it gives me a typeerror that it cant multiply a string or something. Please help
# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"
def squared(var1):
try:
int(var1)
return (var1 * var1)
except ValueError:
a = len(var1)
return (var1 + var1 + var1)
2 Answers
Mark Weiler
579 PointsHi! I have already solve the issue.
Kevin Stewart
5,709 PointsJust to add to this - your variable a isn't currently being used. Any input of type str will always return itself times 3, regardless of its length. Here's an alternative solution.
def squared(item):
try:
if isinstance(item, str):
return item * len(item)
else:
return item * item
except ValueError:
print('Unexpected input type')