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Python Python Collections (2016, retired 2019) Dictionaries String Formatting with Dictionaries

Posted by Michael Gallego
Michael Gallego
1,568 Points

Please tell me what I did wrong. I finally got the output I was expecting but it's wrong :(

I put a for loop of the list of dictionaries, then used each value of x as my reference to the dictionary keys so I can format the text {name} and {food} and append it to the new_list, then finally return the new list, like it said. I tested it on the shell and got exactly what was on the output of the example.

string_factory.py 
# Example:
# values = [{"name": "Michelangelo", "food": "PIZZA"}, {"name": "Garfield", "food": "lasagna"}]
# string_factory(values)
# ["Hi, I'm Michelangelo and I love to eat PIZZA!", "Hi, I'm Garfield and I love to eat lasagna!"]
new_list = []
def string_factory(list_of_dictionary):
    for x in list_of_dictionary:
        new_list.append("Hi, I'm {name} and I love to eat {food}".format(name=x["name"], food=x["food"]))
    return new_list



template = "Hi, I'm {name} and I love to eat {food}!"

1 Answer

Manish Giri
Manish Giri
16,266 Points
Manish Giri
Manish Giri
16,266 Points

I'm assuming they want you to use ** for unpacking. This is my working code - 

template = "Hi, I'm {name} and I love to eat {food}!"

def string_factory(ldict):
    res = []
    for i in ldict:
        res.append(template.format(**i))
    return res
Michael Gallego
Michael Gallego
1,568 Points

Thank you it worked :). They are so specific for answers gosh lol

Manish Giri
Manish Giri
16,266 Points
Manish Giri
Manish Giri
16,266 Points

Glad you got it. Here's the same code (cleaned up a bit) using list comprehension - 

template = "Hi, I'm {name} and I love to eat {food}!"

def string_factory(ldict):
    return [template.format(**i) for i in ldict]