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Domenico Logozzo
3,578 Pointsprinter() missing 1 required positional argument: 'count'
Trying to figure out what I'm missing here. The program ran in the workspace but won't run here? Thanks
def printer(word, count):
return(word) * count
print(printer("Hi ",10))
3 Answers
Chris Freeman
Treehouse Moderator 68,426 PointsThe challenge says "Write a function named printer. The function should take a single argument, count, and should print 'Hi ' as many times as the count argument."
count should be the only parameter specified:
def printer(count):
print("Hi " * count)
Innocent Ngwaru
7,554 Pointsis there anything wrong with my code?
def printer(count):
if count == '6':
print(6 * 'Hi\n')
printer("6")
Chris Freeman
Treehouse Moderator 68,426 PointsIf you're not trying to solve the challenge the code is fine.
While legal code, it will not pass the challenge. It only works for a string value of count. The challenge wants count to be an int. The code also adds a newline char after each "Hi" instead of a space.
Innocent Ngwaru
7,554 PointsThank you Freeman. I was using that code for the challenge, until I got another way through.
Domenico Logozzo
3,578 PointsDomenico Logozzo
3,578 Pointsthanks this works in the shell but also keeps returning Bummer! Didn't find the right number of "Hi"s.
Chris Freeman
Treehouse Moderator 68,426 PointsChris Freeman
Treehouse Moderator 68,426 PointsRight. The challenge wants the value printed not returned. Answer updated.