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Patrick Shushereba
10,911 PointsPrinting the ordinal Ruby
I'm trying to write a program that will print the ordinal of a number that you enter. Here is what I have so far:
puts "Enter a number:"
num = gets.chomp.to_i
ones_place = num % 10
tens_place = num % 100
if ones_place == 1 && tens_place == 1
puts "#{num}th"
elsif ones_place == 1
puts "#{num}st"
elsif ones_place == 2 && tens_place != 1
puts "#{num}nd"
elsif ones_place == 3
puts "#{num}rd"
else
puts "#{num}th"
end
This works for a lot of numbers, but it is still having trouble. When I enter 212, I expect "212th" and I'm getting "212nd" Can someone help me? I know that I'm not too far off, but I'm having trouble seeing it.
3 Answers
Angela Visnesky
20,927 Pointsfrom your code: elsif ones_place == 2 && tens_place != 1 puts "#{num}nd"
ones_place = 212 % 10 leavess a remainder of 2 (which satisfies the first half of your elsif) tens_place = 212 % 100 leaves a remainder of 12(which satisfies the second half)
Patrick Shushereba
10,911 PointsAlright I've got the program working:
puts "Enter a number:"
num = gets.chomp.to_i
ones_place = num % 10
tens_place = num % 100
if tens_place >= 11 && tens_place <= 19
puts "#{num}th"
end
if ones_place == 0
puts "#{num}th"
elsif ones_place == 1
puts "#{num}st"
elsif ones_place == 2
puts "#{num}nd"
elsif ones_place == 3
puts "#{num}rd"
else
puts "#{num}th"
end
But the problem that I'm having now is that it's printing both the right answer, and the wrong answer I was getting before. How can I resolve that?
Angela Visnesky
20,927 PointsHave you tried combining the two if statements into one?
if tens_place >= 11 && tens_place <= 19 puts "#{num}th" elsif ones_place == 0 puts "#{num}th".....
Patrick Shushereba
10,911 PointsI don't quite get what you mean. I'm going to try and rewrite the program as a method and see if that helps my understanding.
Patrick Shushereba
10,911 PointsI don't quite get what you mean. I'm going to try and rewrite the program as a method and see if that helps my understanding.