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Python Python Basics (2015) Shopping List App Break

Mike Coleman
Mike Coleman
3,938 Points
Posted by Mike Coleman
Mike Coleman
3,938 Points

problem with breaks.py

This code runs in my python interpreter and does what the I believe the challenge is asking for (iterate through a list until "STOP" is found).

But it won't pass the challenge. Any thoughts?

breaks.py 
def loopy(items):
    # Code goes here
    for thing in items:
        if thing == "STOP":
            break

        print thing

2 Answers

jcorum
jcorum
71,830 Points
jcorum
jcorum
71,830 Points

Mike, close! But you need an else, and print is a method:

def loopy(items):
    for thing in items:
        if thing == "STOP":
            break
        else:
            print(thing)
Alexander Davison
Alexander Davison
65,469 Points
Alexander Davison
Alexander Davison
65,469 Points

I like jcorum's answer! However, you don't even need an else, like this:

def loopy(items):
    for thing in items:
        if thing == "STOP":
            break
        print(thing)

This is because first, it checks if thing == "STOP", and if so, it will break out of the loop, not allowing the other code in the loop (after the break keyword) to run. So if I run this:

for x in range(10):
    print(x)
    break
    print("Hello!")

Python will only print out "0" (remember, Python starts counting form 0) and the loop will break, and also not running the print("Hello!") part.

Hope that helps!