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Ruby Ruby Basics (Retired) Ruby Methods Method Returns: Part 2

Tyler Martin
Tyler Martin
3,535 Points
Posted by Tyler Martin
Tyler Martin
3,535 Points

Problem with Ruby Code Challenge

Create a method called "mod" that takes two arguments, "a" and "b", and returns the remainder of "a" when divided by "b". Hint: remember the "%" operator!

def mod(a,b)
  return a % b
end

mod (3,2)

This is what I did and it gives me an error. I feel like I'm missing something obvious here.

5 Answers

Nathan Williams
seal-mask
.a{fill-rule:evenodd;}techdegree
Nathan Williams
Python Web Development Techdegree Student 6,851 Points
Nathan Williams
.a{fill-rule:evenodd;}techdegree
Nathan Williams
Python Web Development Techdegree Student 6,851 Points

Hi Tyler,

You wouldn't want to put a space between the function name and the parentheses that wrap your parameters

i.e.

mod(3,2)

but not

mod (3,2)

Hope that helps!

Annie Scott
Annie Scott
27,613 Points
Annie Scott
Annie Scott
27,613 Points

def mod(a, b) return a % b end

Tyler Martin
Tyler Martin
3,535 Points
Tyler Martin
Tyler Martin
3,535 Points

Thank you that did it!

dr disrespekt
dr disrespekt
2,010 Points
dr disrespekt
dr disrespekt
2,010 Points

Thx I needed help on this to I just had puts instead of return. How do we know the difference when asked to write a method?? Im good at everything all the syntax but when asked to do something im clueless the wording stumps me.

lina Hernandez
lina Hernandez
4,583 Points
lina Hernandez
lina Hernandez
4,583 Points

def mod(a,b) return a % b end

mod (3,2)