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Start your free trialJamal Scott
9,656 PointsPython
Cant seem to get this one right, i have this so far
EXAMPLE
import random
random_item("Treehouse")
def random_item("Treehouse"): num = random.randint(0, len("Treehouse")-1) letter = [num] return letter
The randomly selected number is 4.
The return value would be "h"
Many thanks
# EXAMPLE
import random
# random_item("Treehouse")
def random_item("Treehouse"):
num = random.randint(0, len("Treehouse")-1)
letter = [num]
return letter
# The randomly selected number is 4.
# The return value would be "h"
1 Answer
Evan Demaris
64,262 PointsHi Jamal,
The parameter of your function is a string, where it should be a variable. Your letter
variable is a list with one item in it, which is the random integer created, instead of being the random letter; if you pushed all your code into one line, skipping the variable assignment and putting that code into the index for the iterable input of your function, it will pass and will be more efficient;
import random
def random_item(iterable):
return iterable[random.randint(0, len(iterable)-1)]
Please let me know if you have any questions about how or why that works!
adrian lineweaver
Courses Plus Student 565 Pointsadrian lineweaver
Courses Plus Student 565 Pointswhere is iterable defined? is it a string I'm confused?
Evan Demaris
64,262 PointsEvan Demaris
64,262 PointsThe function isn't being used in this example, so the iterable parameter isn't anything yet - it's a placeholder variable. However, iterable would be a string that you provide. So for example,
random_item("catfish")
would return a random letter of "catfish".