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Start your free trialSebastiaan van Vugt
Python Development Techdegree Graduate 13,554 PointsPython Basics (2015) Challenge Task 3 of 3 does not accept what seems to be an appropriate solution...
This is my solution which I tested successfully in the workspace:
try: num1 = int(input("What is the first number you would like to add? ")) num2 = int(input("What is the second number you would like to add? ")) float(num1) float(num2) except ValueError: 0 else: print(num1 + num2)
With this solution task 1 is not passing anymore. In the workspace I can however not seem to add a return argument in the try function (I hope I'm naming these correctly). Simply said I cannot work from the answer of task 2 which is this:
def add(num1, num2): return float(num1) + float(num2)
To a workable try function as described that would also be accepted...
Thank you for your ideas on what the "right" model answer should be here.
try:
num1 = int(input("What is the first number you would like to add? "))
num2 = int(input("What is the second number you would like to add? "))
float(num1)
float(num2)
except ValueError:
0
else:
print(num1 + num2)
2 Answers
Steven Parker
231,236 PointsYour workspace program functions a bit differently from what the challenge is asking for.
Some of the things needed by the challenge:
- you still need to have everything inside a function named "add"
- the values you will use are passed in as arguments, so you will not need to "input" anything
- the function must return the results
- you won't need to "print" anything
- when an exception occurs, you need to return None
- the "float" function doesn't change its argument, so you'll need to assign the result to use it
Sebastiaan van Vugt
Python Development Techdegree Graduate 13,554 PointsThanks a lot for the advice. I didn't realise before that the exception could be dealt with in the function. I have figured it out now though :)
def add(num1, num2): try: float(num1) float(num2) except ValueError: return None else: return(float(num1) + float(num2))