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Python Python Collections (2016, retired 2019) Lists Disemvowel

Posted by Matt Fuller
Matt Fuller
8,831 Points

Python Collections (2016, retired 2019) - challenge task 1 of 1

Took quite a break from self learning coding, absolutely clueless with this one. Can anyone please explain?

disemvowel.py 
def disemvowel(word):
    vowels = ("a", "e", "i", "o", "u")
    word = input("what word would you like to disemvowel?\n> ")
    if not vowels == 'word':
        exit()
    else:
        print ("Removing vowels.")
        word.remove(vowels)
Kito Middleton
Kito Middleton
3,340 Points
Kito Middleton
Kito Middleton
3,340 Points

You need to iterate over the string to check if any of those vowels are equal to any of the letters in the string being passed to function...

1 Answer

Jeff Muday
MOD
Jeff Muday
Treehouse Moderator 28,722 Points
Jeff Muday
Jeff Muday
Treehouse Moderator 28,722 Points

Since this is a coding Challenge. It has an automated grader, so you are NOT supposed to user interactive input() function.

But you look like you do understand some Python concepts, so let's build on that.

There are many correct approaches to this problem. One way is to make a new_word that does not contain vowels. This is accomplished by iterating over the word letter by letter and checking if the letter is NOT a vowel.

Hint: the grader will check both upper and lower case vowels too!

def disemvowel(word):
    vowels = 'aeiouAEIOU'
    # the new_word starts as an empty string
    new_word = ''
    for letter in word:
        # check if the current letter is NOT a vowel, copy it into the new_word
        # and the vowels are skipped
        if not(letter in vowels):
            new_word += letter
    # finally, return the new_word
    return new_word