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Python Python Collections (2016, retired 2019) Dictionaries Word Count

William Heilman
William Heilman
1,764 Points
Posted by William Heilman
William Heilman
1,764 Points

Python Collections Challenge help

Hello - when I test this code in terminal I get the expected results, but for some reason when I paste it into the Challenge, I get a 'Bummer!' message. Can anyone tell me why this doesn't meet the challenge criteria?

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(test_string):
    lwr_string = test_string.lower()
    list_string = lwr_string.split(" ")
    dict_string = {}
    final_dict = {}
    for item in range(0,len(list_string)):
        dict_string = {list_string[item]:list_string.count(list_string[item])}
        final_dict.update(dict_string)


    return final_dict

1 Answer

William Heilman
William Heilman
1,764 Points
William Heilman
William Heilman
1,764 Points

I figured it out. I wasn't splitting on all whitespace, but just a " ". changed it to lwr_string.split(), worked like a champ