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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by dongli2
dongli2
2,362 Points

Python Collections: Word Count. I don't know what's wrong with my code

I tried several methods to solve it, and each time my code works fine locally.

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easie
def word_count(args):
    args = args.lower().split(" ")
    result = dict()
    for each in args:
        each_count = result.get(each, 0)
        result.update({each: each_count+1})
        # result.update({each: args.count(each)})
    return result

1 Answer

Chris Howell
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.a{fill-rule:evenodd;}techdegree seal-36
Chris Howell
Python Web Development Techdegree Graduate 49,702 Points
Chris Howell
.a{fill-rule:evenodd;}techdegree seal-36
Chris Howell
Python Web Development Techdegree Graduate 49,702 Points

Hey dongli2

So you are really close, the Bummer message actually has the hint in it.

Hmm, didn't get the expected output. Be sure you're lowercasing the string and splitting on all whitespace!

HINT is "all whitespace", at the moment you are ONLY splitting on a space or " ".

Python Docs: Split

Be sure to read the "If sep is not specific or is None" section. ;)

dongli2
dongli2
2,362 Points

Thank you so much. Great help to me.