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Python Python Collections (2016, retired 2019) Dictionaries String Formatting with Dictionaries

Posted by thomas2017
thomas2017
1,342 Points

python dictionary unpacking

I got an error that says string_factory() takes 0 positional arguments but 1 was given. I'v seen the right way to do it, but I'm curious as to why this way doesn't work? Is it because values is a list and I can't unpack it this way? thanks for any post

values = [{"name": "Michelangelo", "food": "PIZZA"}, {"name": "Garfield", "food": "lasagna"}, {"name": "Kenneth", "food":"tacos"}]


def string_factory(**kwargs):
    result_list = []
    for item in values:
         template = "Hi, I'm {} and I love to eat {}!".format(name, food)
        result_list.append(template)
        return result_list
string_factory.py 
# Example:
# values = [{"name": "Michelangelo", "food": "PIZZA"}, {"name": "Garfield", "food": "lasagna"}]
# string_factory(values)
# ["Hi, I'm Michelangelo and I love to eat PIZZA!", "Hi, I'm Garfield and I love to eat lasagna!"]

template = "Hi, I'm {name} and I love to eat {food}!"

1 Answer

Anuj Bhusari
Anuj Bhusari
12,240 Points
Anuj Bhusari
Anuj Bhusari
12,240 Points

you have to loop it for all dictionaries in the passed parameter Then add it in another list, and return this new list.

def string_factory(list_of_dicts):

new_list = [] 

for dict in list_of_dicts: 

new_list.append(template.format(**dict)) 

return new_list