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Python Python Basics (2015) Shopping List App Continue

Posted by oshayne anderson
oshayne anderson
839 Points

python pass

Same idea as the last one. My loopy function needs to skip an item this time, though. Loop through each item in items again. If the character at index 0 of the current item is the letter "a", continue to the next one. Otherwise, print out the current member. Example: ["abc", "xyz"] will just print "xyz".

breaks.py 
def loopy(items):
    # Code goes here
a = a[0]
for a in items:
    if a == 'a':
        pass
else:
    continue

2 Answers

james south
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
james south
Front End Web Development Techdegree Graduate 33,271 Points
james south
.a{fill-rule:evenodd;}techdegree seal-36
james south
Front End Web Development Techdegree Graduate 33,271 Points

you can drop the a=a[0] line and just directly compare a, your loop variable, sliced to just the first letter, so it would be if a[0] == 'a'. then instead of pass you need continue, to continue to the next item if the first letter of the item is 'a'. the else needs to hold the print statement, since it wants you to print elements that don't start with 'a'.

Modou Sawo
Modou Sawo
13,141 Points
Modou Sawo
Modou Sawo
13,141 Points

Hi Oshayne,

Do the solution step by step, and you'll find it easy. Firstly, Make sure your code is inside the function (meaning, indent it - see where it says # code goes here). Okay.

So the problem is asking you to loop through every item in items using a for loop. Thus you do:

def loopy(items):
    for item in items:  # notice the new line is indented
    # now add the if condition like you did, you indented that one, NICE! 
        if item[0] == "a":
            continue  #  It's better to write continue, pass is mostly used when u create a function w/o anything in it
        else:
            print(item)

Key thing to remember here is, you're asked to write a for loop to loop through each ITEM in ITEMS, and to create an if-else statement to query through the ITEMS, in order to neglect only the first/zero index item (IF it's equal to "a").