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Start your free trialEva Trapecar
2,123 PointsquerySelectorAll
let listItems = document.querySelectorAll('#Rainbow'); const colors = ["#C2272D", "#F8931F", "#FFFF01", "#009245", "#0193D9", "#0C04ED", "#612F90"];
for(var i = 0; i < colors.length; i ++) {
listItems[i].style.color = colors[i];
}
<!DOCTYPE html>
<html>
<head>
<title>Rainbow!</title>
</head>
<body>
<ul id="rainbow">
<li>This should be red</li>
<li>This should be orange</li>
<li>This should be yellow</li>
<li>This should be green</li>
<li>This should be blue</li>
<li>This should be indigo</li>
<li>This should be violet</li>
</ul>
<script src="js/app.js"></script>
</body>
</html>
let listItems = document.querySelectorAll('#Rainbow');
const colors = ["#C2272D", "#F8931F", "#FFFF01", "#009245", "#0193D9", "#0C04ED", "#612F90"];
for(var i = 0; i < colors.length; i ++) {
listItems[i].style.color = colors[i];
}
1 Answer
Steven Parker
231,248 PointsYour selector should target the list items inside the unordered list.
You might want to use a descendant selector or a child selector to select the right elements.
Also, you spelled "Rainbow" with a capital "R", but it should be "rainbow".
Eva Trapecar
2,123 PointsThank you Steven!
Angelica Hart Lindh
19,465 PointsAngelica Hart Lindh
19,465 PointsWhat's your question here Eva ?