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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by mellowmushroom
mellowmushroom
9,250 Points

Question about implementing function word_count

Im not sure why my code is not being accepted. This is the result for when i pass the example parameter into the function:

word_count("I do not like it Sam I Am")

{'i': 2, 'do': 1, 'not': 1, 'like': 1, 'it': 1, 'sam': 1, 'am': 1

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(string):
    string = string.lower() 
    string = string.split(' ')
    dictionary = {}
    for word in string:
        x = string.count(word)
        dictionary.update({word: x})
    return dictionary
Chris Jones
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
Chris Jones
Java Web Development Techdegree Graduate 23,933 Points
Chris Jones
.a{fill-rule:evenodd;}techdegree seal-36
Chris Jones
Java Web Development Techdegree Graduate 23,933 Points

That's weird. I tried something similar and it worked in the Python shell, but didn't work in the quiz. Maybe try contacting Support? I started at Treehouse with Python and I think I remember the quiz questions being very picky....

def word_count(string):
    d = {}
    string = string.lower();
    word_list = string.split(' ')

    for word in word_list:
        d[word] = word_list.count(word)
    return d

Python 3.5.1 (v3.5.1:37a07cee5969, Dec  6 2015, 01:38:48) [MSC v.1900 32 bit (Intel)] on win32
Type "copyright", "credits" or "license()" for more information.
>>> d = {}
>>> d
{}
>>> string = 'I do not like it Sam I Am'
>>> string
'I do not like it Sam I Am'
>>> string.lower()
'i do not like it sam i am'
>>> string = string.lower()
>>> string
'i do not like it sam i am'
>>> d
{}
>>> string
'i do not like it sam i am'
>>> word_list = string.split(' ')
>>> word_list
['i', 'do', 'not', 'like', 'it', 'sam', 'i', 'am']
>>> for word in word_list:
    d[word] = word_list.count(word)


>>> d
{'it': 1, 'do': 1, 'like': 1, 'i': 2, 'not': 1, 'am': 1, 'sam': 1}
>>>

2 Answers

Stuart Wright
Stuart Wright
41,119 Points
Stuart Wright
Stuart Wright
41,119 Points

The problem is that you need to split on all whitespace rather than simply ' ', as there are different types of whitespace characters. So just use .split() without any argument, since all whitespace characters is the default.

It's picky for sure, but it's what you need to do to pass the challenge.

mellowmushroom
mellowmushroom
9,250 Points
mellowmushroom
mellowmushroom
9,250 Points

Thanks guys!