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Ruby

Posted by xwzotwvqqj
xwzotwvqqj
16,571 Points

Question: Why does the hash show when I do not include a finish "print_seperator"?

Hi, so after this video, I tried making my own version of the grocery list, with a word collector.

It works, but if I remove the last "puts print_separator", the result is:

Dutch word: Hoi
Spanish word: Ola
Finished? (y/n)y

--------------------------------------------------------------------------------
    Dutch word: Hoi     Spanish word: Ola
{"Hoi"=>"Ola"}

Why is this?

See code:

def ask_words
    @word_combi = Hash.new
    done = ""

      until done == "y"
        print "Dutch word: "
        dutch_word = gets.chomp

        print "Spanish word: "
        spanish_word = gets.chomp

        @word_combi.store( dutch_word, spanish_word )

        print "Finished? (y/n)"
        done = gets.chomp
      end

  end

  def print_separator(character="-")
    print character * 80
  end

  def print_list
    puts print_separator
    @word_combi.each do |dutch, spanish|
      puts "\tDutch word: " + "#{dutch}" + "\t\t" + "Spanish word: " + "#{spanish}"
    end
    puts print_separator
  end

  puts ask_words()
  puts print_list()