Quiz keeps telling me I'm wrong about logging numbers, but the preview works fine

Question

With this question: Create a for loop that logs the numbers 4 to 156 to the console. To log a value to the console use the console.log( ) method.
I used this script:
``javascript
var html = '';
for (var i = 4; i <= 156; i += 1) {
  html += i + ' ';
     }
     console.log(html);
``
In my log it shows the numbers from 4 to 156, but I keep getting this message:
Bummer! You need to log out EVERY number from 4 to 156 to the console. Your loop calls the console.log() method 1 times
Anybody can tell me where I'm going wrong?
```script.js
var html = '';
for (var i = 4; i <= 156; i += 1) {
  html += i + ' ';
     }
     console.log(html);
```

Michal Janek · Accepted Answer

They need you to log out the numbers during the loop as a part of it. What you are doing is concatenating a string and storing it in a variable and after the loop is done then you console.log it out just once. While visually it may seem similar to what you are expected to do, functionally it is very different.
So think about it again where is the difference or check the solution bellow.
This is what they are after:
Javascript
for (var i = 4; i <= 156; i +=1 ) {
    console.log(i);
}

or
```Javascript 
for (var i = 4; i < 157; i++ ) {
    console.log(i);
}
```

frits vd Velden · Answer

Sorry, I wish I could, but I haven't got the code anymore. Didn't save it.

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frits vd Velden

frits vd Velden

Quiz keeps telling me I'm wrong about logging numbers, but the preview works fine

2 Answers

Michal Janek

Michal Janek

frits vd Velden

frits vd Velden

Michal Janek

Michal Janek

frits vd Velden

frits vd Velden