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Python Python Collections (Retired) Slices sillyCase

Posted by Imer Pacheco
Imer Pacheco
9,732 Points

Regarding the Sillycase challenge in the Python Collections lesson.

My python code evaluated successfully inside of Workspaces before I realized that the challenge requires you to use the .round() method to slice out the first 4 and last 4 indexes in an iterable and return it in a new list. I have not the foggiest idea of how to approach this challenge using the .round() method. Any pokes in the right direction would be much appreciated.

Here is the code that evaluated successfully in Workspaces:

'''python

my_list = "Treehouse"

def sillycase(itr): first = itr[:int(len(itr)/2)] last = itr[int(len(itr)/2):len(itr)]

firstLow = str(first) lastUp = str(last)

new_list = firstLow.lower() + lastUp.upper()

print(new_list)

sillycase(my_list) '''

silly.py 
def sillycase(itr):
  first = itr[:int(len(itr)/2)]
  last = itr[int(len(itr)/2):len(itr)]

  firstLow = str(first)
  lastUp = str(last)

  new_list = firstUP.lower() + lastUp.upper()

  return new_list
Imer Pacheco
Imer Pacheco
9,732 Points

The example code I pasted does not show up with the appropriate line spacing but I think you get the picture.

2 Answers

Bryan Laraway
Bryan Laraway
13,366 Points
Bryan Laraway
Bryan Laraway
13,366 Points

Here's how I did it:

def sillycase(my_string):
  rounded_index = round(len(my_string)/2)
  my_string = my_string[0:rounded_index].lower() + my_string[rounded_index:].upper()
  return my_string
Imer Pacheco
Imer Pacheco
9,732 Points
Imer Pacheco
Imer Pacheco
9,732 Points

Thanks, Bryan! While I was away I was able to pass the challenge with the following code:

def sillycase(itr):
  first = itr[:round(len(itr)/2)]
  last = itr[round(len(itr)/2):len(itr)]
  new_list = first.lower() + last.upper()
  return new_list

I like your approach, though. Well done!