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Ben Hedgepeth
Python Web Development Techdegree Student 10,287 PointsRemoving different types from a list
I'm stuck on how to approach the second part of this challenge. I can't use a for loop due to the shifting nature that .remove() causes in a list.
messy_list = ["a", 2, 3, 1, False, [1, 2, 3]]
# Your code goes below here
new_messy_list = messy_list.insert(0, messy_list.pop(3)) # [1, 'a', 2, 3, False, [1, 2, 3]
2 Answers
Cross Ender
9,567 PointsThe challenge states that it's perfectly OK to use multiple lines.
Try this setup that I made for you:
Fetch the one.
item = messy_list.pop(3)
Move the one to the front of the list.
messy_list.insert(0, item)
Remove any item that is NOT an integer.
messy_list.remove("a") messy_list.remove(False)
messy_list.remove([1, 2, 3])
Glad I could help. =) -- Cross Ender
Cross Ender
9,567 Pointsitem = messy_list.pop(3) messy_list.insert(0, item) messy_list.remove("a") messy_list.remove(False) messy_list.remove([1, 2, 3])
The message above ended up a bit glitchy. =P